Master Math: 4 Essential Solved Word Problems on Time, Age, and Profit/Loss
1. Ram takes twice as much time as Shyam and thrice as much time as Krishna to finish a piece of work. If they can finish the work together in 16 days, how many days will each take to finish it alone?
Solution:
Let the time taken by Ram be x days.
- Time
taken by Shyam = x/2 days
- Time
taken by Krishna = x/3 days
Their 1-day work:
- Ram: 1/x
- Shyam:
2/x
- Krishna:
3/x
Combined 1-day work = 1/16
or, 1/x + 2/x + 3/x = 1/16
or, 6/x = 1/16
or, x = 96
Results:
- Ram:
96 days
- Shyam:
96/2 = 48 days
- Krishna:
96/3 = 32 days
===
2. Sushila's monthly income is Rs. 18,000. She spends
1/5 on snacks, 3/10 on clothes, and 2/5 on transportation. What fraction does
she save, and what is the savings amount?
Solution:
Total Expenditure Fraction = 1/5 + 3/10 + 2/5 = 9/10
- Savings
Fraction: 1 - 9/10 = 1/10
- Savings
Amount: 1/10 of 18,000 = Rs. 1,800
3. Three years ago, the sum of the ages of a father and his son was 48 years. In three years from now, the ratio of their ages will be 3:1. What are their current ages?
Solution:
Let the current ages of the father and son be x and y.
Condition 1: 3 years ago
(x - 3) + (y - 3) = 48
or, x + y - 6 = 48
or, x + y = 48 + 6
or, x + y = 54
or, x = 54 - y .... (i)
Condition 2: 3 years from now
{x + 3} : {S + 3} = 3 : 1
or, {x + 3} / {y + 3} = 3/1
or, x + 3 = 3y + 9 .... (ii)
(Substitute x = 54 - y into the second equation)
or, (54 - y) - 3y = 9 - 3
or, 54 - y - 3y = 6
or, - 4y = - 48
or, y = 12
now, x = 54 - 12 = 42
(Substitute y = 12 into the first equation)
Results:
- Father's
current age: 42 years
- Son's
current age: 12 years
4. By selling a watch for Rs. 4,500, a wholesaler suffers a 10% loss. At what price must he sell it to earn a 10% profit?
Solution:
Step 1: Find the Cost Price (CP)
Selling Price (SP) = Rs. 4,500
Loss = 10%
CP = {SP times 100} / {100 - Loss %}
= {4500 times
100} / {90}
= 50 times 100
= Rs. 5,000
Step 2: Find the New Selling Price for 10% Profit
Target Profit = 10%
New SP = (100+10) % of CP
=
(110/100) x Rs. 5,000
= 1.1
x Rs. 5,000
= Rs.
5,500
...
Practice Set
1. Aayush takes twice as long as Binod and four times as
long as Chirag to complete a task. If all three working together can finish the
task in 12 days, how many days would it take Binod to finish the work alone?
2. A person earns Rs. 40,000 per month. They spend 1/4 on
rent, 2/5 on food, and 1/10 on entertainment.
- What
fraction of the income is saved?
- What
is the total amount spent on food and rent combined?
3. Five years ago, the sum of the ages of a mother and her
daughter was 40 years. In five years from now, the mother will be exactly twice
as old as the daughter. Find their current ages.
4. By selling a mobile phone for Rs. 18,000, a shopkeeper
loses 20%.
- What
was the cost price of the phone?
- At
what price should they sell it to make a 15% profit?

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